Philosophy Lexicon of Arguments

Search  
 
Author Item Excerpt Meta data
Stechow, A. von
 
Books on Amazon
Empty Set 16
empty set / Stechow: is a subset, but not element of any set. - Proof: Let M be an arbitrary set and x is any one thing. We show that the following applies: if x e 0, then x e M. ( "A then B" is equivalent to Not A or B): This is true iff. x ~e 0 or x e M. Now, for every x: x ~ e 0. So the statement that the empty set is subset of any set is valid.
A. von Stechow
I Arnim von Stechow Schritte zur Satzsemantik
www.sfs.uniï·"tuebingen.de/~astechow/Aufsaetze/Schritte.pdf (26.06.2006)




back to list view | > Suggest your own contribution | > Suggest a correction
 
Ed. Martin Schulz, access date 2017-03-31