## Philosophy Lexicon of Arguments | |||

Author | Item | Excerpt | Meta data |
---|---|---|---|

Stechow, A. von Books on Amazon |
Empty Set | 16 empty set / Stechow: is a subset, but not element of any set. - Proof: Let M be an arbitrary set and x is any one thing. We show that the following applies: if x e 0, then x e M. ( "A then B" is equivalent to Not A or B): This is true iff. x ~e 0 or x e M. Now, for every x: x ~ e 0. So the statement that the empty set is subset of any set is valid. |
A. von Stechow I Arnim von Stechow Schritte zur Satzsemantik www.sfs.uniï·"tuebingen.de/~astechow/Aufsaetze/Schritte.pdf (26.06.2006) |

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Ed. Martin Schulz, access date 2017-03-26